Frank Welker Confirms SCOOB! Sequel, Involvement in Velma

[Doo]

On his website, Frank Welker has confirmed that there will be a sequel to SCOOB!, which Tony Cervone had previously hinted at in June. (7th entry down) www.frankwelker.com/letmebefrank

In addition, in an interview at GalaxyCon, Frank confirmed he will be in Velma. He hints it is not one of his regular characters, however. In the interview, he said the show "is loosely based on the Scooby-Doo characters, and it's kind of a different version of all that. But the character I play is a little different sounding for me, so when I come back to it, they'll play a reference tape." Here's a link to that spot in the interview: www.youtube.com/watch?t=353&v=nVUay83cUXc&feature=youtu.be

[Ark]

Wow. I knew about the sequel rumor, but Welker playing Velma and Scooby and not Fred? Am I understanding correctly? I'm curious, don't get me wrong, but I'm a bit worried about how this will proceed into the future.

[scoobylover]

Great find! I’m so happy they’re bringing him in for Velma, looks like they wanna give us a lot of easter eggs, just like when Casey Kasem voiced Shaggy’s dad or Linda Cardellini as Hot Dog Water

[russm]

So their messing over of the existing VAs continues.

[Doo]

Dec 13, 2021 2:34:49 GMT -5 Ark said:

Wow. I knew about the sequel rumor, but Welker playing Velma and Scooby and not Fred? Am I understanding correctly?

No, Welker is playing a character in the HBO Max series called Velma. He hasn't revealed who the character is. I see what happened though, I meant to say he will be IN Velma (as in the series), but I apparently forgot the word "in" lol.

[Ark]

Oh! If it's like Casey Kasem being the dad in MI, that's actually a neat idea.

[Doo]

Dec 13, 2021 13:14:43 GMT -5 Ark said:

Oh! If it's like Casey Kasem being the dad in MI, that's actually a neat idea.

That would be so cool if he was Velma's dad!

[cometcrystal]

I'm happy Frank will be there even if it's not as Fred or Scooby. He's such an integral part of the franchise at this point.